6 mo. ago • 100%

[2024/05/03] Infinite exponential

Find x for x^xx^xx^... = 2

3 comments

Now try x^xx^… = 4. And then tell me why it’s not a logical crisis that you get exactly the same answer when you solve x^xx^… = 2 instead.

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First off, why did this post get downvoted?

Answer alert

The answer is sqrt(2), because sqrt(2)² = 2, and you build the infinite exponential sequence by taking x_n = x^x_(n-1).

0
- yup there u go, btw can u please spoiler it so its harder for people to accidentally see it
  
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