That was my initial thought, but you can do add or sub by 2 (6 / 3) to get a non-multiple of 3. I had to double check and see that there were in fact values of i.e. x.5 within I think a difference of 64, can’t remember the exact values or their expressions.
Factorials or something more than basic arithmetic (+exponents) is needed as I went ahead and programmatically checked every expression without parenthesis and the closest would always be 195. Interestingly, all values within a difference of 10 were multiples of 3.
A lost cause indeed.
I’m now committed to getting this to work, but I’m not quite there.
(6^3) - 6 * 3 - 3 = 195 Beyond this, I’m quite lost on how this can be done with simple arithmetic.
Kind of a knee-jerk reaction to it on my part, plus I’ve got personal bias against exceptions (errors as values my beloved). The worst thing is that thinking about this code has managed to take time I could’ve used being non-productive with my own projects smh.