1 yr. ago • 97%

i++

11 comments

Takes 1 more character, that's bloat.

5
- 2 more
  
  1
Thanks, i hate it

3
I saw while(i --> 0) in someone else's code and thought wth is this --> operator? Then I realized it's while(i-- > 0) and thought cool, I gotta do this!

2
Someone forgot to set their phone to do not disturb

1
this is incredibly cursed. i love it.

1
Isn't the evaluated value different from the expression? i++ returns the value of i before increasing. i-=-1 would return the value after it has been increased. Wouldn't it be more correct to make it equal to ++i

0
- And that's why post- and pre-increment is non-existant in Python and Rust. It's an easy source for bugs for a noncritical abbreviation🤷
  
  0
  
  They're especially also a source of bugs, because they encourage manually incrementing indices and manually accessing array positions, which is almost never actually sensible.
  
  -1
- In the languages I know, i-=-1 or x=3 are not expressions, but rather statements, so they do not evaluate to a value.
  
  So, this would be a compiler error:
  
  a = (x=3)
  
  0
  
  Well, not all languages allow for fun programming :)
  
  1

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