Well let's break it down:
- π + π + π = 18
- 3π = 18
- π = 6
- π + (π β’ π) = 5
- 6 + π^2 = 5
- π^2 = -1
- π = I
- π₯€^π - π₯€ = 3
- π₯€^i-1 = 3
- π₯€ = 3^1/(i-1)
Simple!
34ReplyWait, what happened in the second to last bullet point? You can't convert a power like that when subtracting (you can when dividing).
It's like you'd convert "2^4 - 2" into "2^(4-1)", which gives two different results (14 vs 8).
27ReplyFor those curious, I threw π₯€^i - π₯€ = 3 into wolfram.
π₯€ β -2.97983 + 0.0388569 i... or π₯€ β 0.27972 - 0.748461 i...
10ReplyYou're right, idk what I was thinking there π
3Reply
I think they're saying no one can give the real answer to this... which is technically true because the answer is imaginary.
14Replyyou forgot the Β± when square rooting:
π = Β±i
this is because i Γ i = -1 and -i Γ -i = -1
12ReplyBah, yes I forgot about that
3Reply
π = I
Don't you mean π = i?
9ReplyAnd just like that, I'm back to junior high grumbling about the concept of imaginary numbers.
Fuck you, y'all made up! π€£
2ReplyLol I didn't quite get my math right, but it still involves imaginary numbers. Fun fact! Any 3D game you've played in the past probably quarter century doesn't just use 1 dimension of imaginary numbers, but 3 to represent 3D rotation! Quaternions are difficult to visualize since it's a 4-dimensional quantity but they're perfect for representing rotation in 3D space without suffering from gimbal lock like rotation matrices.
1Reply
- π + π + π = 18
I fucked around, and this is what i got:
π + π + π = 18
=> π = 6
π + ( π Γ π ) = 5
πΒ² = -1
=> π = Β±i
(π₯€^ π) -π₯€= 3
case 1: (π₯€^ i) -π₯€= 3
case 2: (π₯€^ -i) -π₯€= 3
at this point, i just used wolfram to get both:
=> {
π₯€ β -2.97983 + 0.0388569 i,
π₯€ β 0.27972 - 0.748461 i
}
Curiously, case 1 and case 2 return the same 2 values...
28ReplyCorrection, 99% of European people canβt solve this. For Americans this just a regular breakfast
15ReplyY'all bitch about math class but it you replace x, y & z withπππ₯€ and suddenly you're all doing math for fun
6ReplyA quarter pounder with cheese
5ReplyYou mean a cheese royal?
2Reply
Math now supports Unicode variables! The progress we all need.
3ReplyLooks like you need a refill.
1Reply-3
0Reply